- #1
Kate L
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I'm really confused by this question, as it is different than the examples we did in class. I've compared my answer with a few classmates and I'm getting a different one, so I'm not sure if I've done it wrong or if they have. I'd really just like to know if I am on the right track! Thank you :)
1. Homework Statement
Blood flows at 0.465 cm/sec through an artery with an inside radius of 2.85 mm. What is the flow speed in another section where the artery radius increases to 4.35 mm? Round final answer to 3 significant figures.
Givens:
v1= 0.465 cm/sec
r1 = 2.85 mm
r2 = 4.35 mm
A1v1=A2v2
A=3.14(r)2
Convert v1 = 0.465 cm/sec to 0.00465 m/sec
Convert r1 = 2.85 mm to 0.00285 m
Convert r2 = 4.35 mm to 0.00435 m
Find A1→ A1=3.14(0.00285)2 = 2.550465x10-5
Find A2→ A2=3.14(0.00435)2 = 5.941665x10-5
A1v1 = A2v2
v2 = (A1v1) ÷ A2
1. Homework Statement
Blood flows at 0.465 cm/sec through an artery with an inside radius of 2.85 mm. What is the flow speed in another section where the artery radius increases to 4.35 mm? Round final answer to 3 significant figures.
Givens:
v1= 0.465 cm/sec
r1 = 2.85 mm
r2 = 4.35 mm
Homework Equations
A1v1=A2v2
A=3.14(r)2
The Attempt at a Solution
Convert v1 = 0.465 cm/sec to 0.00465 m/sec
Convert r1 = 2.85 mm to 0.00285 m
Convert r2 = 4.35 mm to 0.00435 m
Find A1→ A1=3.14(0.00285)2 = 2.550465x10-5
Find A2→ A2=3.14(0.00435)2 = 5.941665x10-5
A1v1 = A2v2
v2 = (A1v1) ÷ A2
= [2.550465x10-5(0.00465)] ÷ 5.941665x10-5
= 1.996016647x10-3
= 2.00x10-3 m/sec
= 1.996016647x10-3
= 2.00x10-3 m/sec