Estimating the Probability of Nuclear Power Plant Damage from Rare Tsunamis

In summary: Is that what you get?Yes, that is correct. Good job summarizing the content. In summary, the problem is asking for the probability of a nuclear power plant being damaged by a tsunami within its 65-year lifespan, given an estimated frequency of 1 in 200 years. This can be calculated using the formula for probability of no damage, with the given rate of 1/200. This results in a probability of 0.259, which is commonly referred to as a pessimistic failure rate of 'one tomorrow'.
  • #1
hworth
3
0

Homework Statement



The frequency of a tsunami large enough to threaten the safety of a nuclear power plant has been estimated to be 1 in 200 years. If the plant’s life is 65 years what is the probability it will be damaged by such a tsunami? What is this probability more commonly termed?
[2 Marks]

Homework Equations



How do you get a base event failure rate for components with no recorded failures in an operating time T? Let λ = k/T. A Pessimistic Failure Rate λ = 1/T is known as ‘one tomorrow’. A PSA could use k = 0.5525 (For the estimation of failure rates for low probability events see Progress in Nuclear Energy 4 374-476 1997).

The Attempt at a Solution



Probability of no damage = e-λT

λ = 0.5525/200

Probability of damage = 1-e-(0.5525/200)(60) = 0.153

A pessimistic failure rate λ=1/T is known as 'one tomorrow'.

Is this correct or completely wrong? Thank you
 
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  • #2
hworth said:
How do you get a base event failure rate for components with no recorded failures in an operating time T? Let λ = k/T. A Pessimistic Failure Rate λ = 1/T is known as ‘one tomorrow’. A PSA could use k = 0.5525 (For the estimation of failure rates for low probability events see Progress in Nuclear Energy 4 374-476 1997).
You are overthinking this. The problem statement gives you the rate. Where this number comes from is a different question not relevant here.
 
  • #3
mfb said:
You are overthinking this. The problem statement gives you the rate. Where this number comes from is a different question not relevant here.

Are you sure? So would you say 0.325? Seems too simple.
 
  • #4
You'll still need the exponential function.
 
  • #5
mfb said:
You'll still need the exponential function.

Do you get 0.259?

λ = 1/200
Probability of damage = 1-e-(1/200)(60) = 0.259
 
  • #6
That's how I would answer the problem.
 

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