Exactly why FTLC is impossible with entangled photons?

[Karagoz]

Now suppose that Alice changes her angle to something else, which we'll call $\theta$. The stream of photons reaching Bob is made up 50% of photons polarized along the angle $\theta$ and 50% polarized along the angle $\theta+\pi/2$.

So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?

 

[bhobba]

I don't understand why you two are arguing when you both must believe that a separable conditional probability $P(xy|\alpha\beta)=P(x|\alpha)P(y|\beta)$ cannot reproduce the predictions of QT ?

Beats me as well. All I am saying is the rules of normal probability theory are not respected in QM which is hardly surprising since it is a different probability model. If you want it to be like ordinary probability theory you need non-locality. But for some reason he thinks Bell has nothing to do with probability.

Thanks
Bill

 

[Mentz114]

So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?

If a photon does not pass a filter it is gone. All the photons that pass a polarizer are aligned to the polarizer angle.

 

[Nugatory]

So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?

The ones that arrive at Bob with polarization $\phi+\pi/2$ also encounter Bob's filter and contribute to the number passing through it. What is $\cos^2(\phi+\pi/2)$?

 

[Karagoz]

The ones that arrive at Bob with polarization $\phi+\pi/2$ also encounter Bob's filter and contribute to the number passing through it. What is $\cos^2(\phi+\pi/2)$?

We are talking aboit a new set of entangled photons when Alice changes his polarization filter. So almost same thing happens again.

Thanks, I think I got it if I'm not wrong.

 

[bhobba]

The question has been answered so its time to close it.

Thanks
Bill