- #1
Mr Davis 97
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This might be a dumb question, but I am wondering, given the equation ##A\vec{x} - 7\vec{x} = \vec{0}##, the factorization ##(A - 7I)\vec{x} = \vec{0}## is correct rather than the factorization ##(A - 7)\vec{x} = \vec{0}##. It seems that I can discribute just fine to get the equation we had before using the second ##(A - 7)\vec{x} = \vec{0}##, so I'm not sure why I would think to do ##(A - 7)\vec{x} = \vec{0}## rather than ##(A - 7I)\vec{x} = \vec{0}##.