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fight_club_alum
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Homework Statement
A uniform rod (mass = 1.5 kg) is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The rod is released from rest in a horizontal position. What is the angular speed of the rod when the rod makes an angle of 30 degrees with the horizontal? (The moment of inertia of the rod about the pin is 2 kg m^2)
Homework Equations
mg(H intial - H final) =1/2 I w^2
The Attempt at a Solution
My attempt:
M = 1.5 kg
L = 2 m
Moment of inertia (I) = 2 kg m^2
mg(H intial - H final) =1/2 I w^2
1.5 x 9.8 x 2sin(30) = 1/2 x 2 x w^2
w^2 = 14.7
w = 3.64
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