Find the eigenvalues and eigenvectors for the matrix

tomeatworld
Messages
49
Reaction score
0

Homework Statement


Find the eigenvalues and eigenvectors for the matrix [{13,5},{2,4}]

Homework Equations


None

The Attempt at a Solution


Well eigenvalues is easy, and turn out to be 14 and 3.
So using eigenvalue 3, the two equations 10x1 + 5x2=0 and 2x1 + x2=0. Using these, I assumed the eigenvector to be [1,-2] but after putting it into Wolfram (or mathematica) it gives out the vector should be [-1,2]. Is there a difference? How should you discern between the two if not and where have I gone wrong if there is?
 
Physics news on Phys.org


tomeatworld said:

Homework Statement


Find the eigenvalues and eigenvectors for the matrix [{13,5},{2,4}]

Homework Equations


None

The Attempt at a Solution


Well eigenvalues is easy, and turn out to be 14 and 3.
So using eigenvalue 3, the two equations 10x1 + 5x2=0 and 2x1 + x2=0. Using these, I assumed the eigenvector to be [1,-2] but after putting it into Wolfram (or mathematica) it gives out the vector should be [-1,2]. Is there a difference? How should you discern between the two if not and where have I gone wrong if there is?
Assuming your work is correct, there is no difference between <1, -2> and <-1, 2> as far as being eigenvectors. Each of these vectors is the -1 multiple of the other, so they are both in the same eigenspace, a subspace of dimension 1 (a line) in R2.
 


Great. So do programs like mathematica choose them at random or is there a reason it chose <-1,2> over <1,-2>?
 


Ok, thanks for the help!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top