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- Homework Statement
- A square steel plate is 10.0 cm on a side and 0.500 cm thick.
Find the shear strain that results if a force of magnitude ##9.0\times10^5N## is applied to each of the four sides, parallel to the side. Plate is in equilibrium.
Find the displacement x in centimeters.
- Relevant Equations
- Shear stress ##=\frac FA##, shear strain ##=\frac xh##, ##S_\text{steel}=7.5\times10^{10}##
$$S=\frac FA\frac hx\Leftrightarrow\frac{F}{SA}=\frac xh=\text{shear strain}\\
\frac xh=\frac{9.0\times10^5}{10.0\times0.500\times10^{-4}\times7.5\times10^{10}}=1.2\times10^{-3}\\
x=1.2\times10^{-3}\times0.500=6.0\times10^{-4}\,cm$$
I'm doing something wrong, any help?
\frac xh=\frac{9.0\times10^5}{10.0\times0.500\times10^{-4}\times7.5\times10^{10}}=1.2\times10^{-3}\\
x=1.2\times10^{-3}\times0.500=6.0\times10^{-4}\,cm$$
I'm doing something wrong, any help?