MHB Finding sum of infinite geometric series

AI Thread Summary
The discussion centers on finding the sum of the infinite geometric series 1 - √2 + 2 - 2√2 + ... Participants analyze the common ratio, concluding that it equals 2. Since the absolute value of the common ratio exceeds 1, the series diverges. Therefore, the correct answer is that the series diverges, confirming option c. The calculations and reasoning emphasize the importance of the common ratio for determining convergence in geometric series.
fluffertoes
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find the sum of this infinite geometric series:
1 - √2 + 2 - 2√2 + ...

a.) .414
b.) -2.414
c.) series diverges
d.) 2

I found that the common difference is 2, so I calculated this:

S= -.414/-1
s= .414

So i got that the answer is A, but will you check this?
 
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In order for this to be a geometric series, we must have:

$$S=(1-\sqrt{2})\sum_{k=0}^{\infty}\left(a^k\right)$$

Going by the terms given, it appears that $a=2$, and so what does this tell us about the convergence?
 
MarkFL said:
In order for this to be a geometric series, we must have:

$$S=(1-\sqrt{2})\sum_{k=0}^{\infty}\left(a^k\right)$$

Going by the terms given, it appears that $a=2$, and so what does this tell us about the convergence?

oh gosh i don't know
 
fluffertoes said:
oh gosh i don't know

Recall that:

$$\sum_{k=0}^{\infty}r^k=\frac{1}{1-r}$$ but only if $|r|<1$

Otherwise, the sum diverges. :D
 
MarkFL said:
Recall that:

$$\sum_{k=0}^{\infty}r^k=\frac{1}{1-r}$$ but only if $|r|<1$

Otherwise, the sum diverges. :D

But r stood to equal 2, so the answer should be c?
 
fluffertoes said:
but r stood to equal 2, so the answer should be c?

hello??
 
fluffertoes said:
But r stood to equal 2, so the answer should be c?

Yes.

fluffertoes said:
hello??

Sorry, but I was working on a coding request at vBorg. (Sweating)
 

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