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A projectile fired from ground level at 25 m/s hits the ground 31.25 m away. At what angle was it fired?
I wrote equations for t for both x and y
t = delta x / velocity x
t = 2 * viy/a
and set them equal to each other to eliminate t
and replaced velocityx with cos(theta)*25
and replaced velicityinitialy with sin(theta)*25
delta x / cos(theta)*25 = 2*sin(theta)*25/a
25 / cos(theta)*25 = 2*sin(theta)*25/9.81
sin(theta) * 25 * cos(theta)*25 = 153.28
My trig is not that good. How do I continue? Or is this even the right way to tackle this proble? Is there an easier way?
I wrote equations for t for both x and y
t = delta x / velocity x
t = 2 * viy/a
and set them equal to each other to eliminate t
and replaced velocityx with cos(theta)*25
and replaced velicityinitialy with sin(theta)*25
delta x / cos(theta)*25 = 2*sin(theta)*25/a
25 / cos(theta)*25 = 2*sin(theta)*25/9.81
sin(theta) * 25 * cos(theta)*25 = 153.28
My trig is not that good. How do I continue? Or is this even the right way to tackle this proble? Is there an easier way?