- #1
bobie
Gold Member
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Homework Statement
This is not homework,
I'd like to know if it is possible to find the pitch a log spiral knowing that at every round (2π) r grows by 535.5 times.
For the little I know the equation should be just r = e2π = 535.5
Supposing it starts at r=1cm and goes clockwise, I have guessed that its length should be 755.88 cm. and pitch=45° ,
but according to Torricella formula pitch should be ≈44.85°, since the whole length should be ≈ 759 cm and [itex]\varphi[/itex]= ≈45.15°
so that 535.3/cos[itex]\varphi[/itex] =759 cm and 759-755.9 = 3 cm which is too much for the curve from 1 to 0, isn't it?
Can anyone make a graph?
Thanks a lot.
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