Finding the Ricci tensor for the Schwarzschild metric

In summary: Keep up the good work! In summary, you have made good progress in using Cartan's method and have correctly calculated some of the components of the Ricci tensor. To obtain the remaining components, you can use the relation mentioned above and the components of the inverse metric tensor that you have already calculated.
  • #1
saadhusayn
22
1
I'm trying to use Cartan's method to find the Schwarzschild metric components from Hughston and Tod's book 'An Introduction to General Relativity' (pages 89-90). I'm having problems calculating the components of the Ricci tensor.

The given distance element is

$$ ds^2 = e^{2 \lambda} dt^2 - e^{2 \mu} dr^2 - r^2({d \theta^2}+ \sin^2 \theta
d\phi^2) $$

Thus ##g_{\mu \nu} = \text{diag}(e^{2 \lambda}, -e^{2\mu}, -r^2, -r^2 \sin^2\theta)## and
##g^{\mu \nu} = \text{diag}(e^{-2\lambda}, -e^{-2\mu}, -\frac{1}{r^2}, -\frac{1}{r^2 \sin^2 \theta})##

Using Cartan's structure equations, I have worked out the Ricci tensor components ##R_{011}^{\space\space\space\space\space\space 0}##, ##R_{022}^{\space\space\space\space\space\space 0}##, ##R_{033}^{\space\space\space\space\space 0}##, ##R_{122}^{\space\space\space\space\space\space 1}##,##R_{133}^{\space\space\space\space\space\space 1}##and ##R_{233}^{\space\space\space\space\space\space2}##. Then
$$ R_{00} = R_{0\rho0}^{\space\space\space\space\space\space \rho} =
R_{000}^{\space\space\space\space\space\space 0}+
R_{010}^{\space\space\space\space\space\space 1} + R_{020}^{\space\space\space\space\space\space 2} + R_{030}^{\space\space\space\space\space\space 3} $$

Now ##R_{000}^{\space\space\space \space \space 0} = 0## by antisymmetry of the first two indices.
The last 3 terms look like the known components ##R_{011}^{\space\space\space\space\space\space 0}##, ##R_{022}^{\space\space\space\space\space\space 0}##, ##R_{033}^{\space\space\space\space\space 0}## except with adjacent upstairs and downstairs indices switched. Is the following how we obtain them?

##R_{abc}^{\space\space\space \space \space d } = g^{de} R_{abce} = -g^{de} R_{abec} = -g_{cf}g^{de} R_{abe}^{\space\space\space \space \space f}##. Now ##\because## the metric is a diagonal one, the only surviving term is the one for which ##f = c## and ##d = e##. Therefore,

##R_{abc}^{\space\space\space \space \space d} = - g_{cc}g^{dd}R_{abd}^{\space\space\space \space \space c} ## (no summation)

So, for example,

$$R_{010}^{\space \space \space \space \space 1} = -g_{00}g^{11} R_{011}^{\space \space \space \space \space 0} = -(e^{2\lambda}) (-e^{-2\mu}) R_{011}^{\space \space \space \space \space 0}$$

...and so on and so forth for the other Riemann tensor components.

If it isn't, how would we get these components from the known components of the Riemann tensor? Thank you!
 
Last edited:
Physics news on Phys.org
  • #2


Hello,

Thank you for sharing your work and question on using Cartan's method to find the Schwarzschild metric components. It looks like you have a good understanding of the method and have made some progress in calculating the Ricci tensor components. However, I would like to clarify a few things and offer some suggestions for obtaining the remaining components.

Firstly, it is important to note that the components ##R_{abc}^{\space\space\space \space \space d}## are not the same as the Ricci tensor components ##R_{\mu \nu}##. The components ##R_{abc}^{\space\space\space \space \space d}## are the components of the Riemann tensor, which is a different tensor than the Ricci tensor. The Riemann tensor is a 4th order tensor, while the Ricci tensor is a 2nd order tensor.

To obtain the Ricci tensor components, you can use the following relation:

$$R_{\mu \nu} = R_{\mu \rho \nu}^{\space\space\space\space\space\space \rho} $$

where ##R_{\mu \rho \nu}^{\space\space\space\space\space\space \rho}## are the components of the Ricci tensor in the mixed form (one upper index and one lower index). These components can be calculated using the relation you have mentioned:

$$R_{\mu \rho \nu}^{\space\space\space\space\space\space \rho} = g^{\rho \sigma} R_{\mu \rho \nu \sigma} $$

where ##R_{\mu \rho \nu \sigma}## are the components of the Riemann tensor in the mixed form. So, for example, to obtain the component ##R_{010}##, you can use the following relation:

$$R_{010} = R_{010}^{\space\space\space\space\space\space \rho} = g^{\rho \sigma} R_{010 \sigma} $$

where ##g^{\rho \sigma}## are the components of the inverse metric tensor, which you have already calculated. Similarly, you can obtain the other Ricci tensor components using the same method.

I hope this helps clarify the difference between the Riemann tensor and the Ricci tensor and
 

1. What is the Ricci tensor in general relativity?

The Ricci tensor is a mathematical object used in the study of general relativity, a theory that describes the gravitational interactions of massive objects. It is a symmetric tensor that encodes information about the curvature of a four-dimensional spacetime. In other words, it describes how the geometry of spacetime is affected by the presence of massive objects.

2. How is the Ricci tensor related to the Schwarzschild metric?

The Schwarzschild metric is a mathematical representation of the curvature of spacetime outside a spherically symmetric, non-rotating mass. It is described by the Ricci tensor, which is derived from the Einstein field equations using the Schwarzschild metric as a solution. In fact, the Ricci tensor is one of the terms in the Einstein field equations, which describe the relationship between the curvature of spacetime and the distribution of matter and energy.

3. What is the significance of finding the Ricci tensor for the Schwarzschild metric?

Finding the Ricci tensor for the Schwarzschild metric is important because it allows us to understand the behavior of massive objects in a curved spacetime. It is a crucial step in solving the Einstein field equations and obtaining solutions that describe the gravitational effects of massive objects. In the case of the Schwarzschild metric, it helps us to understand the curvature of spacetime outside a non-rotating mass, such as a black hole.

4. How is the Ricci tensor calculated for the Schwarzschild metric?

The Ricci tensor for the Schwarzschild metric can be calculated using the mathematical technique of tensor calculus. It involves performing various mathematical operations on the Schwarzschild metric, such as taking derivatives and performing contractions, to obtain the components of the Ricci tensor. Alternatively, it can also be calculated using computer software, which can handle the complex calculations involved in tensor calculus.

5. What are the implications of the Ricci tensor for our understanding of gravity?

The Ricci tensor, along with the other terms in the Einstein field equations, provides a mathematical framework for understanding gravity in the context of general relativity. By studying the Ricci tensor, we can gain insights into the behavior of massive objects in a curved spacetime, such as the bending of light and the formation of black holes. It also helps us to make predictions and test the validity of general relativity in different scenarios, such as near extremely massive objects or in the early universe.

Similar threads

  • Advanced Physics Homework Help
Replies
3
Views
869
  • Advanced Physics Homework Help
Replies
6
Views
1K
  • Advanced Physics Homework Help
Replies
10
Views
2K
  • Advanced Physics Homework Help
Replies
20
Views
2K
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
7
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
1K
Back
Top