- #1
vinci
- 12
- 4
Homework Statement
A crane lifts its 500N load to the top of the building from A to B. Distances are shown on the diagram. Calculate how much work is done by the crane
Known variables:
AB= displacement= 50m
AC=horizontal distance=30m
BC=vertical distance=40m
2. Homework Equations
Work done= force * distance covered in direction of force
W=F.S
Force=mass* acceleration
F=ma
Hypotenuse= Root ( Adjacent^2 + Opposite^2 )
The Attempt at a Solution
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From the diagram it can be seen that there the DISPLACEMENT is AB or 50 M. The load is 500N which will require a force in upward direction of 500N. I am confused with which variables to use but nevertheless
Work done in upward direction(BC):
W=FS
=500N*40M=20000NM
Work done in horizontal direction(AC):
W=FS
=500N*30M=15000NM I'm unsure about this one if 500N force will be required because we are not pushing a body on the ground and not countering a friction of 500N
Work done in AB?
W=FS
=500N * 50M =25000NM
(This can't be right can it? Because from what I think the crane will first lift the weight up and then rotate)
This is a simple high school question and I might be overcomplicating it but I am really confused which variables to use since the question should have ONE answer.