- #1
mateomy
- 307
- 0
We're going over the intro stuff to integration and we are being asked to find the value of the sums...
Here's the problem I am getting stuck on...
[tex]
\sum_{i=1}^{n} (i^2 + 3i + 4)
[/tex]
I know that I have to separate the individual sums, so I put it into this form...
[tex]
\sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4
[/tex]
And then I know the individual forms of the Riemann sums of i^2 and i, etc.
[tex]
\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc...
[/tex]
am I just adding these together as if they were fractions (finding common denominators, etc)?
Here's the problem I am getting stuck on...
[tex]
\sum_{i=1}^{n} (i^2 + 3i + 4)
[/tex]
I know that I have to separate the individual sums, so I put it into this form...
[tex]
\sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4
[/tex]
And then I know the individual forms of the Riemann sums of i^2 and i, etc.
[tex]
\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc...
[/tex]
am I just adding these together as if they were fractions (finding common denominators, etc)?