- #1
toothpaste666
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Homework Statement
A water tank, 3.7 m deep and 2 m in diameter, is connected at the bottom to a second water tank by using a 2 cm diameter pipe (see the figure). The tank A is open to the air and tank B is filled to the top and sealed.
a) what is the mass of the water in tank A?
b)what is the gauge pressure at the bottom of tank A?
c) what is the absolute pressure at the bottom of tank B?
d) what is the net force on the top of tank B?
Homework Equations
P=ρgh
The Attempt at a Solution
a) to find the mass of the water in tank A
m= ρv = ρAh = ρ(PiD^2/4)h = ρ(Pi(2)^2/4)h = ρPih = (1000)(3.14)(3.7) = 12000
m = 12000
b) to find the gauge pressure at the bottom of tank A
P = ρgh = (1000)(9.8)(3.7) = 3600
P = 3600
c) absolute pressure at bottom of tank B
gauge pressure = P = ρgh
h = 3-1 = 2 , 3.7-2 = 1.7, 1.7+3 = 4.7
h= 4.7
P = ρgh = (1000)(9.8)(4.7) = 46000
absolute pressure = gauge pressure + atmospheric pressue
AP = 46000 + (1.013x10^5) = 147300
absolute pressure = 147300
d) net force at top of tank B. the water here isn't moving so the net force must be = 0.
I think my solution might be wrong because it makes no use of the info about the connecting tube. Not sure where I went wrong