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It appears in the second step: CH3Ialingy1 said:
The process of forming ether from alkyl halide is known as Williamson ether synthesis. It involves the reaction of an alkyl halide with a deprotonated alcohol to form an ether.
The reagents required for Williamson ether synthesis are an alkyl halide and a deprotonated alcohol. The conditions usually involve the use of a strong base, such as sodium hydride or potassium hydroxide, and a polar aprotic solvent, such as dimethyl sulfoxide (DMSO) or tetrahydrofuran (THF).
Forming ether from alkyl halide is a common method for synthesizing ethers, which are important functional groups in many organic compounds. Ethers can also be used as solvents or as intermediates in the synthesis of other compounds.
No, not all alkyl halides are suitable for Williamson ether synthesis. Alkyl halides that are primary or secondary and have a good leaving group, such as iodide or bromide, are most commonly used. Tertiary alkyl halides may also be used, but they can undergo competing elimination reactions.
One limitation of Williamson ether synthesis is that it cannot be used to form ethers with tertiary alcohols, as they do not easily deprotonate. Additionally, this method may result in the formation of side products or byproducts, such as elimination products or rearranged products, which can reduce the overall yield of the desired ether.
