- #1
Eduardo
- 2
- 0
Homework Statement
Show that the range [tex]\mathcal{R}(T)[/tex] of a bounded linear operator [tex]T: X \rightarrow Y[/tex] is not necessarily closed.
Hint: Use the linear bounded operator [tex]T: l^{\infty} \rightarrow l^{\infty}[/tex] defined by [tex](\eta_{j}) = T x, \eta_{j} = \xi_{j}/j, x = (\xi_{j})[/tex].
Homework Equations
The Attempt at a Solution
My idea was to find an element [tex]y \in l^{\infty}[/tex] that does not belong to the range and then try to build a convergent sequence in [tex]\mathcal{R}(T)[/tex] that has limit [tex] y [/tex]. The element [tex]y = (1, 1, \ldots)[/tex] satisfy the criteria because [tex]T^{-1}y = \{ x\}[/tex], with [tex]x = (\xi_{j}), \xi_{j} = j[/tex], but, clearly, [tex]x \not\in l^{\infty}[/tex], therefore, [tex]y \not\in \mathcal{R}(T)[/tex]. The problem arise when I try to build the sequence, because [tex](T x_{m})[/tex] with [tex]x_{m} \in l^{\infty}[/tex] cannot converge to [tex] y [/tex]. Briefly, my problem is that I can´t find a limit point of [tex]\mathcal{R}(T)[/tex] that doesn´t belong to [tex]\mathcal{R}(T)[/tex].