- #1
Apteronotus
- 202
- 0
Hi,
The Poisson equation (or Gauss Law) in a vacuum is given by
[itex]\nabla^2\phi=-\frac{\rho}{\epsilon_0}[/itex]
where [itex]\rho \mbox{ and } \epsilon_0[/itex] are the charge density and vacuum permittivity or (electric constant of space).
My question is what is the Gauss's Law in a dielectric material? Do we simply replace the vacuum permittivity by the permittivity of the material?
ie.
[itex]\nabla^2\phi=\frac{\rho}{\epsilon_r}[/itex]
where above [itex]\epsilon_r[/itex] is the relative permittivity (or permittivity of the dielectric material).
Thanks,
The Poisson equation (or Gauss Law) in a vacuum is given by
[itex]\nabla^2\phi=-\frac{\rho}{\epsilon_0}[/itex]
where [itex]\rho \mbox{ and } \epsilon_0[/itex] are the charge density and vacuum permittivity or (electric constant of space).
My question is what is the Gauss's Law in a dielectric material? Do we simply replace the vacuum permittivity by the permittivity of the material?
ie.
[itex]\nabla^2\phi=\frac{\rho}{\epsilon_r}[/itex]
where above [itex]\epsilon_r[/itex] is the relative permittivity (or permittivity of the dielectric material).
Thanks,