- #1
Poirot
- 94
- 2
Homework Statement
Calculate the circumference of the circle θ = θ0 (a constant) in the spatial geometry
\begin{eqnarray*}
dS^2 = a^2(d\theta^2 + sin^2\theta cos^2\theta d\phi^2)
\end{eqnarray*}
Hence, (by finding R(z)) sketch the cross section of the surface embedded in three dimensions via
\begin{eqnarray*}
(x, y, z) = (Rsin\theta cos\phi, Rsin\theta sin\phi, Rcos\theta)
\end{eqnarray*}
Homework Equations
The Attempt at a Solution
Calculating the circum:
Parameterising the path set φ = τ, where τ1 = 0 and τ2 =2π, and θ = θ0 (const.)
so
\begin{eqnarray*}
circumference = \int_{0}^{2\pi} \frac{dS}{d\tau}d\tau = \int_{0}^{2\pi} a((\frac{d\theta}{d\tau})^2 + sin^2\theta cos^2\theta (\frac{d\phi}{d\tau})^2)^{1/2} d\tau
\end{eqnarray*}
using the parametrisation we get:
\begin{eqnarray*}
circumference: \int_{0}^{2\pi} a sin\theta_0 cos\theta_0 d\tau = 2\pi a sin\theta_0 cos\theta_0 = \pi a sin2\theta_0
\end{eqnarray*}
I'm not at all sure what the next part is getting at. I've played around with rearranging z=Rcosθ and plugging this in for theta in metric but I don't think that's right.
Any help would be great appreciated, thank you!