Getting the init. velocity given G-force?

In summary, the problem involves a cart with no friction being pushed with a g-force of 2.6 for a distance of 1600 ft. The cart then stops but continues to move. The question is asking for the initial velocity after the cart is released. The weight of the cart is 230.3lbf and there is no friction. While the given information may seem insufficient, kinematics equations can still be used to solve the problem. The distance of 1600 ft is important as it sets the region over which the acceleration occurs.
  • #1
MartinSa
2
0

Homework Statement


If an object is horizontally pushed with a g-force of 2.6 (imagine a cart with no friction on the wheels being in constant contact with a pusher being pushed for 1600 ft at that g-force and then stops but the cart keeps moving) what is the initial velocity right after it's let go?
230.3lbf weight of cart
no friction

Homework Equations


kinematics aren't useful since I don't have enough information

The Attempt at a Solution


the 1600 ft I am sure is irrelevant because the cart has the same g-force throughout and is always in contact with the pusher.
F = 598.78 lbf
 
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  • #2
Hi MartinSa,
Welcome to Physics Forums!

MartinSa said:

Homework Statement


If an object is horizontally pushed with a g-force of 2.6 (imagine a cart with no friction on the wheels being in constant contact with a pusher being pushed for 1600 ft at that g-force and then stops but the cart keeps moving) what is the initial velocity right after it's let go?
230.3lbf weight of cart
no friction

Homework Equations


kinematics aren't useful since I don't have enough information
Not true. You have a constant acceleration and a distance. You should be able to find one of the SUVAT equations that will yield a final velocity.

The Attempt at a Solution


the 1600 ft I am sure is irrelevant because the cart has the same g-force throughout and is always in contact with the pusher.
Can you explain why you think contact with the "pusher" makes the distance irrelevant?

The distance is very important: It's the value that you're given that sets the region over which the acceleration occurs. You can set the boundary by either time or distance and there are SUVAT equations to deal with both cases.
 

1. What is the formula for calculating initial velocity given G-force?

The formula for calculating initial velocity given G-force is v = √(2 x g x d), where v is the initial velocity, g is the acceleration due to gravity (9.8 m/s2), and d is the distance traveled.

2. How do you convert G-force to acceleration?

To convert G-force to acceleration, you can use the formula a = g x G, where a is the acceleration and G is the G-force. For example, if the G-force is 5G, the acceleration would be 49 m/s2 (9.8 x 5).

3. Can initial velocity be negative when calculating G-force?

Yes, initial velocity can be negative when calculating G-force. A negative initial velocity indicates that the object is moving in the opposite direction of the acceleration due to gravity.

4. How does air resistance affect the calculation of initial velocity given G-force?

Air resistance can affect the calculation of initial velocity given G-force by slowing down the acceleration of the object. In order to accurately calculate the initial velocity, the effect of air resistance should be taken into account.

5. What units are typically used for G-force and initial velocity?

G-force is typically measured in multiples of the acceleration due to gravity (g), such as 1G, 2G, etc. Initial velocity is typically measured in meters per second (m/s).

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