Hall Effect and Drift Velocity

[Staple Gun]

Homework Statement

A thin metal film of length 1.00 cm, width of 0.250 cm, and thickness of 29.0 micrometers is used to measure the Hall effect. A current of 2.60 A is maintained along the length of the sample. The Hall voltage of 16.0 microVolts is detected across its width, when a magnetic field of 2.00 Tesla is applied normal to the film.
Calculate the drift velocity of the charge carriers.

Homework Equations

V_h = IB/ned
I=neAV_d

V_h = Hall Voltage
V_d = Drift Velocity
I = Current
B = Magnetic Field
n = Number of electrons
e = Charge of particle
A = area
d = Thickness of film

The Attempt at a Solution

Using equation 1 I got n = IB/V_hed
Then I plugged that into equation 2 and solved for V_d but this answer is incorrect.

Any help would be greatly appreciated! Thanks

 

[thepanda]

The drift velocity is what makes the magnetic field, so I think the equation should be:

q Vh *width = q Vd B

So Vd = Vh * width/B

 

[Staple Gun]

Using that equation I got Vd = 16e-6 * 0.0025 / 2.00 = 2.00e-8 m/s

This answer was incorrect though.