- #1
JennyLee1989
- 10
- 4
- Homework Statement
- A 7 kg sample of mercury is completely solidified and liberates 81.06 kJ of energy.
What is the original temperature of the mercury? (The melting point of mercury is
234 K, the heat of fusion of mercury is 11.3 kJ/kg, and the specific heat of mercury is
140 J/kgÂK.) 4) A) 2.0 K B) 240 K C) 850 K D) 580 K
- Relevant Equations
- Q=mc(Tf-Ti)-mL+mc(Tf-Ti)
I have used the heat equation and am not able to get the initial heat. This is what I have so far:
81060 = 7 * 140 * (change in temp) - (7 * 11300) + 7 * 140 ( change in temp)
I found the change in temp to be 81.71K. But that does not help me with the initial temperature!
81060 = 7 * 140 * (change in temp) - (7 * 11300) + 7 * 140 ( change in temp)
I found the change in temp to be 81.71K. But that does not help me with the initial temperature!