- #1
Demio Crush
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question : a car traveling at constant speed 20m/s overtakes another car which is moving at constant acceleration of 2 m/s^2 and it’s initially at rest . assume the length of each car to be 5 meters . thetotal road distance used in overtaking is ...
my attempt : for overtaking , t = distance between car 1 and car 2 + 5+5+5 / 20-2t
20-2t is the average velocity .
with this I get a quadratic equation , which I had to solve by formula method . But , for my method 2 variables are unknown .
Been trying this problem for past 2 hours . help please . I'll be really glad .
my attempt : for overtaking , t = distance between car 1 and car 2 + 5+5+5 / 20-2t
20-2t is the average velocity .
with this I get a quadratic equation , which I had to solve by formula method . But , for my method 2 variables are unknown .
Been trying this problem for past 2 hours . help please . I'll be really glad .