Help Needed: Exploring the Force of Water & Weight of a Jetliner

[PhysicsHelp08]

I'm having a lot of trouble with fluids I need some help on these two questions :/

the mariana trench is located in the floor of the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of seawater is 1025 kg/m^3.
if an underwater vehicle were to explore such a depth, what force would the water exert on the vehicles observation window (radius=.10m)?
For comparison, determine the weight of a jetliner whose mass is 1.2x10^5 kg

The aorta carries blood away from the heart at a speed of 40 cm/s and has a radius of 1.1cm. The aorta branches eventually into a large number of tiny capillaries that distribute the blood to various organs. In a capillary, the blood speed is about .07 cm/s and the radius is about 6x10^-4cm. Treat the blood as an incompressible fluid, and use these data to determine the approximate number of capillaries in the human body

any help please? thanks a lot!

 

[MuffinMan616]

Ok... I am new to this forum but I noticed your post and thought I'd lent a hand. I am enrolled in Advanced Placement Physics at my high school and we already went over fluids so I think i can help.

For your first question:

P = p*g*h
P = F/A
A = pi*r^2
--so--
F=P*A
--and--
F=p*g*h*pi*r^2

and the other part:

F = ma
--so--
Fg = m*g

For the second question:

It is flow rate...

AV(before) = AV(after)
A = pi*r^2
--so--
pi*r^2*V = pi*r^2*V

since there are multiple capilaries...

r(of aorta)^2*V(of a.)
------------------------ (divided by) = Number of capilaries
r(of capilaries)^2*V(of c.)

Hope this helped

 

[Moetasim]

I am happy to assist with your questions regarding fluids. Let's start with the first question about the force of water at the bottom of the Mariana Trench. To calculate this, we can use the formula F = ρghA, where ρ is the density of the fluid (in this case, seawater), g is the acceleration due to gravity (9.8 m/s^2), h is the depth (11,000 m), and A is the area of the observation window (πr^2, where r is the radius of 0.10 m). Plugging in these values, we get a force of approximately 34,000 N.

Now, moving on to the comparison with the weight of a jetliner. The weight of an object is equal to its mass multiplied by the acceleration due to gravity. So, for the jetliner with a mass of 1.2x10^5 kg, its weight would be roughly 1.18x10^6 N.

For the second question, we can use the equation Q = A1v1 = A2v2, where Q is the flow rate, A is the cross-sectional area, and v is the velocity. We can assume that the flow rate is constant throughout the aorta and the capillaries, so we can set the two equations equal to each other. Solving for the number of capillaries (n), we get n = (A1v1)/(A2v2). Plugging in the given values, we get approximately 2.5x10^9 capillaries in the human body.

I hope this helps with your understanding of fluids. If you have any further questions, please don't hesitate to ask. Keep up the curiosity and good luck with your studies!