- #1
woodworker101
- 19
- 0
I am still having troubles with Newtons laws and i work with the problems but get an answer but don't know if it is the right one and just want to check my work with yours to see if I am correct.
An airplance with a mass of 1.2 x 10^4 kg tows a glider with a mass of .60 x 10^4 kg. If the airplace propellers provide a net forward thrust of 3.6 x 10^4 N, what is the acceleration of the glider? I believe the answer is 6.0 m/s^2, but not for sure if it right or not.
An Olympic skier moving at 20.0 m/s down a 30.0 degree slope encounters a region of wet snow and slides 145 m before coming to a halt. What is the coefficient of friction between the skies and the snow? I believe it is .740.
Two perpendicular forces, one of 45.0 N directed upward and the second of 60.0 N directed to the right, act simultaneously on an object with a mass of 35.0 kg. What is the magnitude of the resultant acceleration of the object? This I believe is 1.41 m/s^2.
All I am wanting is to see someone else's work on how they got their answer so I can see where I messed up or if I did them correctly or not. Thanks for the help.
An airplance with a mass of 1.2 x 10^4 kg tows a glider with a mass of .60 x 10^4 kg. If the airplace propellers provide a net forward thrust of 3.6 x 10^4 N, what is the acceleration of the glider? I believe the answer is 6.0 m/s^2, but not for sure if it right or not.
An Olympic skier moving at 20.0 m/s down a 30.0 degree slope encounters a region of wet snow and slides 145 m before coming to a halt. What is the coefficient of friction between the skies and the snow? I believe it is .740.
Two perpendicular forces, one of 45.0 N directed upward and the second of 60.0 N directed to the right, act simultaneously on an object with a mass of 35.0 kg. What is the magnitude of the resultant acceleration of the object? This I believe is 1.41 m/s^2.
All I am wanting is to see someone else's work on how they got their answer so I can see where I messed up or if I did them correctly or not. Thanks for the help.