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ann
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Member advised to use the homework template for posts in the homework sections of PF.
Can someone please explain to me why in this problem, for example, the sine and cosine functions are used in equating the force's components? I am having a hard time solving for these unknown forces because of my rusty trig skills.
It asks to "determine the maximum weight of the flowerpot that can be supported without exceeding a cable tension of 50lb in either cable AB or AC." My professor provided these calculations:
∑Fx=0
F_AC*sin(30)-F_AB*cos(53.13)=0
50*sin(30)-F_AB*cos(53.13)=0
F_AB=41.66lb
∑Fy=0
F_AC*cos(30)+F_AB*sin(53.13)-W=0
50*cos(30)+41.66*sin(53.13)-W=0
W=76.63 lb
Why did they use the sine and cosine functions for this specific problem. Where they used the sine function, for example, why couldn't they have used a tangent function instead?
It asks to "determine the maximum weight of the flowerpot that can be supported without exceeding a cable tension of 50lb in either cable AB or AC." My professor provided these calculations:
∑Fx=0
F_AC*sin(30)-F_AB*cos(53.13)=0
50*sin(30)-F_AB*cos(53.13)=0
F_AB=41.66lb
∑Fy=0
F_AC*cos(30)+F_AB*sin(53.13)-W=0
50*cos(30)+41.66*sin(53.13)-W=0
W=76.63 lb
Why did they use the sine and cosine functions for this specific problem. Where they used the sine function, for example, why couldn't they have used a tangent function instead?