How dense would an object have to be in order to hold up a makeshift earth.

[Tirent]

I know that this may be very odd,but I wanted to calculate the density of the pillar of the world from the God of War franchise.This pillar by itself as small as it is is able to hold the Earth up quite easily. So i just wanted to have an estimation of how dense an object like a pillar would have to be in order to hold up an Earth sized planet with the same weight of earth.

Let's just factor these in and just assume that

>The gravity is the same as earth's
> The pillar is 1000m in height and has a 4x4 base so a side would be about 100m
>The pillar is on top of a stable flat surface.
>The pillar is a rectangular prism.

Also just a quick question,which of the following could successfully hold up this fake Earth without being crumbled?

1.A sky scraper
2.10 sky scrapers
3.A Mountain of 1000 meters
4.Mount Olympus
5.All of the mountains in the Earth put together into one giant mountain
6.an island separated from the water that is about the size of Jamaica
7.The same as above but the island is the size of Texas
8.A continent ripped from earth(Africa)
9.multiple Africas(3)
10.A moon

Or simply can you just tell me how much something would have to weigh in order to hold this fake Earth up.

 

[Tirent]

Any input?
Not even on the list?

 

[nasu]

Density is not the relevant parameter here.
The material strength and stiffness parameters determine if the pillar will support the weight or not.

 

[DrZoidberg]

It's not just the strength of the pillar that's important here but also the strength of the earth. Try lifting an elephant up with a sewing needle. The elephants skin isn't strong enough.

 

[pmacias]

First of all, I appreciate your curiosity and interest in calculating the density of objects in relation to fictional scenarios. I will approach this question by considering the laws of physics and using some basic calculations to provide an estimation of the required density for an object to hold up a makeshift Earth.

To begin, we need to understand the concept of density. Density is the measure of how much mass is contained within a given volume. It is calculated by dividing the mass of an object by its volume. In the case of your question, we need to determine the density of the pillar that is holding up the makeshift Earth.

Based on the information provided, we can calculate the volume of the pillar as follows:

Volume = length x width x height
= 100m x 100m x 1000m
= 10,000,000 m^3

Next, we need to determine the mass of the Earth. According to NASA, the mass of the Earth is approximately 5.972 × 10^24 kg. This means that the pillar would need to have a mass of at least 5.972 × 10^24 kg in order to hold up the Earth.

Now, we can calculate the required density of the pillar:

Density = mass/volume
= 5.972 × 10^24 kg / 10,000,000 m^3
= 5.972 × 10^18 kg/m^3

To put this into perspective, the density of lead, which is one of the densest materials on Earth, is only 11.34 kg/m^3. This means that the pillar would have to be incredibly dense in order to hold up the Earth.

As for the options given, none of them would be able to hold up the Earth without being crumbled. The weight of the Earth is simply too great for any object or combination of objects to support it without collapsing under the immense pressure. In fact, the Earth's own gravity is what holds it together, not any external object.

In conclusion, the required density for an object to hold up a makeshift Earth would be extremely high and not achievable by any known materials. The laws of physics and the Earth's own gravity make it impossible for any object to hold up the Earth without being crushed.