- #1
sobergeek23
- 20
- 1
Member warned that the homework template must be used
i have no idea how to use the punctuation marks for writing equations..ill do my best..
(3a+4b)(a-3b) over b(3a+4b) multiplied by 1 over b^2(3b-a)(3b+a)
during the cross cancelling the 3b-a would be multiplied by a negative one to switch the problem over right? (-1)(3b-a) in order to cross cancel with the (a-3b) in the top left..
the answer was 1 over b^3(a-3b) but i don't understand the whole negative sign thing..isnt (3b-a) the same as (-a+3b)? so factoring out the negative would make it (a-3b) and it cancels with the top left fraction but then i also have the (b) (b^2)(3b+a) on the bottom so how do they get b^3(a-3b)? i get the b^3 part ..i thought maybe the negative one i factored out in the (3b-a) would have also applied to the (3b+a) but then wouldn't it be (-3b-a) ..im so confussed on factoring out negatives..
(3a+4b)(a-3b) over b(3a+4b) multiplied by 1 over b^2(3b-a)(3b+a)
during the cross cancelling the 3b-a would be multiplied by a negative one to switch the problem over right? (-1)(3b-a) in order to cross cancel with the (a-3b) in the top left..
the answer was 1 over b^3(a-3b) but i don't understand the whole negative sign thing..isnt (3b-a) the same as (-a+3b)? so factoring out the negative would make it (a-3b) and it cancels with the top left fraction but then i also have the (b) (b^2)(3b+a) on the bottom so how do they get b^3(a-3b)? i get the b^3 part ..i thought maybe the negative one i factored out in the (3b-a) would have also applied to the (3b+a) but then wouldn't it be (-3b-a) ..im so confussed on factoring out negatives..