How Do You Calculate Tire Contact Area Using Pascal's Law?

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In summary, to calculate the contact area of each tire on a vehicle with four 20 cm wide tires and 2 atm air pressure, the formula P=F/A or P=ρgh can be used. The gross vehicle weight, 1 tonne, needs to be corrected to 103 kg. Using the formula F=mg, the weight of the vehicle is 9.8x10^6 N. Plugging this into the formula A=F/P, the contact area for each tire is 49 m^2.
  • #1
joe98
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Pascals Law Problem

Homework Statement



You have a vehicle with four tires of 20 cm wide with 2 atm air pressure. Calculate
contact area (cm^2) of each tire on the road. The gross vehicle weight is 1 tonne.


Homework Equations



P=F/A
P=ρgh

The Attempt at a Solution



F=mg=1x10^6x9.8=9.8x10^6

A=F/P
therefore, A=(9.8x10^6)/200000=49m^2

I am not sure if I am right so far,

can u assist me if I am incorreect

cheers
 
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  • #2
Is this method of calculation correct?
 
  • #3


joe98 said:

Homework Statement



You have a vehicle with four tires of 20 cm wide with 2 atm air pressure. Calculate
contact area (cm^2) of each tire on the road. The gross vehicle weight is 1 tonne.


Homework Equations



P=F/A
P=ρgh

The Attempt at a Solution



F=mg=1x10^6x9.8=9.8x10^6
That's a lot of kilograms for a tonne! tonne = 103 kg.
A=F/P
therefore, A=(9.8x10^6)/200000=49m^2
The method is okay for finding the total contact area. Just fix the tonne value.
 
  • #4
ooh thnx gneil much appreciated
 
  • #5


Hi there,

It looks like you are on the right track with your solution. Let's break it down further:

F=mg=1x10^6x9.8=9.8x10^6

This is correct, you have calculated the weight of the vehicle (1 tonne = 1x10^6 grams) and multiplied it by the acceleration due to gravity (9.8 m/s^2) to find the force exerted by the vehicle on each tire.

Now, we can use P=F/A to find the pressure exerted by the vehicle on each tire. You have correctly identified that the pressure (P) is equal to the force (F) divided by the contact area (A). However, in your solution, you have used a pressure of 2 atm, which is given in the problem. Therefore, the correct equation to use would be:

P=F/A

2 atm = (9.8x10^6 g x 9.8 m/s^2)/A

We can simplify this equation by converting grams to kilograms (1 g = 0.001 kg) and rearranging to solve for A:

2 atm = (9.8x10^6 kg x 9.8 m/s^2)/A

A = (9.8x10^6 kg x 9.8 m/s^2)/(2 atm)

A = 4.9x10^6 kg x m/s^2

A = 4.9x10^6 N

This gives us the total contact area for all four tires. To find the contact area for each individual tire, we can divide this value by 4:

A = 4.9x10^6 N/4 = 1.225x10^6 N

Therefore, the contact area for each tire is 1.225x10^6 N or 49 cm^2.

I hope this helps! Let me know if you have any further questions.
 

Related to How Do You Calculate Tire Contact Area Using Pascal's Law?

What is Pascal's Law?

Pascal's Law, also known as the principle of transmission of fluid pressure, states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container. This law is the basis for many hydraulic systems and plays a crucial role in fluid mechanics.

What is a Pascal's Law problem and how do I solve it?

A Pascal's Law problem is a physics problem that involves the application of Pascal's Law to determine various unknowns, such as pressure, force, or area. To solve these problems, you must first identify what is known and unknown, and then use the formula P=F/A, where P is pressure, F is force, and A is area, to solve for the unknown variable. It is important to always use consistent units in your calculations.

What are some real-life applications of Pascal's Law?

Pascal's Law has many practical applications in our daily lives. It is the basis for hydraulic systems, such as car brakes and elevators, where a small force can be multiplied to create a larger force. This law is also used in hydraulic jacks, hydraulic presses, and hydraulic lifts. In addition, it is essential in understanding the circulation of blood in our bodies and the functioning of our organs.

What are some common mistakes made when solving Pascal's Law problems?

One of the most common mistakes made when solving Pascal's Law problems is not using consistent units in calculations. This can lead to incorrect answers. Another mistake is not properly identifying what is known and unknown in the problem, which can result in using the wrong formula or approach. It is also crucial to pay attention to the direction of the forces and pressures involved in the problem.

Are there any limitations to Pascal's Law?

While Pascal's Law is a fundamental principle in fluid mechanics, it does have some limitations. It only applies to confined fluids, meaning that the container must be completely closed. It also assumes that the fluid is incompressible and that there are no external forces acting on the fluid. Additionally, it does not take into account factors such as viscosity and turbulence, which can affect the accuracy of calculations in real-life situations.

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