How Do You Convert Pixel Number to Wavelength in a CCD Spectrum Analysis?

In summary, you produced a colour rendering of the planetary nebula spectrum and determined the wavelength difference between the line centres of adjacent emission lines. You also found that the dispersion of the spectrum was XX Angstroms/pixel.
  • #1
jaykob_hxc
3
0
Hey Guys,

i'm a first year astrophysics student and i got given this question to answer in a practical report:

Examine the spectrum of the planetary nebula derived from the diffraction grating. You will produce a colour rendering of the spectrum together with a graphical representation of intensity versus pixel number.

The pixel number scale can be replaced by a wavelength scale. Given that some of the bright emission lines are due to excited hydrogen and oxygen gas, determine a conversion between pixel number and wavelength. (Draw a graph showing pixel number on the x-axis and wavelength on the y-axis. The graph should be linear).


now i have a pixel vs intensity graph which appears to have three sharp peaks. I'm not quite sure on what I'm supposed to go from here.

thanks for your responses :)
 
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  • #2
Welcome to PF jaykob_hxc!

jaykob_hxc said:
Hey Guys,

i'm a first year astrophysics student and i got given this question to answer in a practical report:

Examine the spectrum of the planetary nebula derived from the diffraction grating. You will produce a colour rendering of the spectrum together with a graphical representation of intensity versus pixel number.

The pixel number scale can be replaced by a wavelength scale. Given that some of the bright emission lines are due to excited hydrogen and oxygen gas, determine a conversion between pixel number and wavelength. (Draw a graph showing pixel number on the x-axis and wavelength on the y-axis. The graph should be linear).


now i have a pixel vs intensity graph which appears to have three sharp peaks. I'm not quite sure on what I'm supposed to go from here.

thanks for your responses :)

The diffraction grating disperses the light in such a way that different wavelengths land in different places along a line on the CCD. So you're just calibrating your measurements into meaningful units by finding the scaling between "horizontal position along CCD" and "wavelength." To do this, you have to identify the spectral lines (intensity peaks) in your spectrum. These lines occur at known wavelengths (because they correspond to electron energy-level transitions in various gases that have been measured in labs here on Earth). Therefore, once you have identified the lines, you'll know what the wavelength difference is supposed to be between the line centres of any two adjacent lines. Compare that to the horizontal distance between them, and this gives you your scaling relation (or "calibration factor") between position on the detector and wavelength. Here's a hint for identifying the lines: planetary nebulae consist of gases whose atoms have been excited by energetic photons from a hot central source in the middle of the nebulae. There is a fairly standard set of "nebular emission lines" that results from this excitation. EDIT: and you've already been told that the lines present are probably hydrogen and oxygen emission lines.
 
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  • #3
thanks for your help cepheid! :)

my lecturer also put this up for anyone who reads this who was also stuck on a simillar question...

If you do a plot of intensity vs pixel number (from the text file for
the spectral profile that you produced in IRIS), you should see three main
peaks.

One of these (I think with the lowest pixel number) will be the zero-order
image of the planetary nebula (which has the catalogue number NGC 6572), and you
don't need to worry with this one in this context.

The two other peaks will be due to hydrogen alpha, and to oxygen III. If the
zero-order image has the lowest pixel number (i.e. x-position) of the three, the
OIII line will be next highest, and the H-alpha line will have the highest pixel
number or x-position.

You will then have a difference in pixel number (difference in x-locations)
corresponding to a difference in wavelength (given that OIII is 5007 Angstroms,
and H-alpha is at 6563 Angstroms).

The dispersion- which is what you're determining- is just (difference in
wavelength)/(difference in pixel number), i.e. XX Angstroms/pixel. (Note that
you need to estimate the pixel number that corresponds to the centre of each
emission line, so probably the pixel number which has the highest intensity, in
each of the OIII and H-alpha emission lines).

For a spectrograph, the dispersion is one of the basic parameters that we need
to know when analysing a spectrum, and using a source which has lines at known
wavelengths (such as a planetary nebula) is one way to calibrate the
spectrograph and its resulting images.

also this link might help.
http://www.physics.adelaide.edu.au/~pmcgee/plaspec.htm

thanks again!
 
  • #4
Pixel saturation is a problem with all ccd cameras. Once a pixel is saturated, it bleeds into adjacent pixels, which confounds the data.
 
  • #5


Hi there! It looks like you have a great start on your practical report. The graph you have created, showing intensity versus pixel number, is a useful tool in analyzing the spectrum of the planetary nebula. The sharp peaks you see represent the bright emission lines from excited hydrogen and oxygen gas, as you mentioned.

To determine the conversion between pixel number and wavelength, you will need to use the graph you have created. First, identify the pixel numbers corresponding to the three sharp peaks. Then, using a ruler, draw a line connecting those points on your graph. This line represents the relationship between pixel number and intensity for those specific emission lines.

Next, you will need to find the wavelength values for those emission lines. This can be done by referring to a spectral line database or by using a spectroscope to directly measure the wavelengths. Once you have those values, plot them on your graph, with wavelength on the y-axis and pixel number on the x-axis. The resulting graph should be a straight line, which will allow you to determine the conversion between pixel number and wavelength for your specific setup.

I hope this helps guide you in your analysis. Good luck with your report!
 

Related to How Do You Convert Pixel Number to Wavelength in a CCD Spectrum Analysis?

1. What is a CCD sensor?

A CCD (Charge-Coupled Device) sensor is a light-sensitive semiconductor device commonly used in digital cameras and other imaging devices. It converts light into electrical signals, allowing images to be captured and digitized.

2. How does a CCD sensor measure intensity?

A CCD sensor measures intensity by converting photons (light particles) into electrons. The number of electrons generated is proportional to the amount of light that hits the sensor, and this data is then converted into digital values.

3. What is the relationship between intensity and pixel number in a CCD sensor?

The intensity of light hitting a CCD sensor is directly related to the number of pixels that are exposed to that light. As the intensity increases, more pixels will be activated and generate a higher number of electrons.

4. How does a CCD sensor handle low and high intensity levels?

CCD sensors have a wide dynamic range, meaning they are able to handle both low and high intensity levels. This is achieved by adjusting the exposure time of each pixel, allowing for accurate capture of both bright and dark areas in an image.

5. Are there any limitations to using a CCD sensor for intensity measurement?

One limitation of using a CCD sensor for intensity measurement is its potential for blooming. This occurs when a pixel is overexposed, causing the excess electrons to overflow into neighboring pixels and distort the image. Additionally, CCD sensors have a slower readout time compared to other types of sensors, which can limit their use in applications that require fast data acquisition.

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