- #1
Rapidrain
- 31
- 0
Just for fun I'd like to find the equation r(t) which defines the position of an apple as a function of time falling from a distance Ro (radius of the earth) down to a basketball with the mass of the earth--probably a black basketball hole.
All websites show the equations for a distance where the gravitational acceleration of the Earth (g = 9.8 m3/s2) is, for all practical purposes, constant--Pisa tower, etc. I am curious as to whether I can show the position in an equation from Ro all the way to the event horizon of my black basketball hole.
I got this far : v(t) = sqrt ( 2*g / r(t) - 2*g/Ro ) //&1
That second member I set to -2*g/Ro because I am dropping the apple from Ro away from the black basketball hole and the initial velocity is 0.
a little algebra gets me : dt = 1/(sqrt(2*g/r(t) - 2*g/Ro)) dr
now I integrate that guy and end up with :
t = (1/sqrt(2*g))*( -r*Ro*sqrt(1/r - 1/Ro) - sqrt(Ro3)(arctan(Ro/r - 1)) //&3
and it doesn't work when using 200, 400, 600 meters
It yields a time which is 55,000,000-fold that of the values calculated using the tower of Pisa-scale formula r = 0.5*g*t2
Is my v(t) formula wrong at &1 ?
Or is my integration wrong in &3?
I've been trying to solve this for two months now, can anybody see an error in my logic?
All websites show the equations for a distance where the gravitational acceleration of the Earth (g = 9.8 m3/s2) is, for all practical purposes, constant--Pisa tower, etc. I am curious as to whether I can show the position in an equation from Ro all the way to the event horizon of my black basketball hole.
I got this far : v(t) = sqrt ( 2*g / r(t) - 2*g/Ro ) //&1
That second member I set to -2*g/Ro because I am dropping the apple from Ro away from the black basketball hole and the initial velocity is 0.
a little algebra gets me : dt = 1/(sqrt(2*g/r(t) - 2*g/Ro)) dr
now I integrate that guy and end up with :
t = (1/sqrt(2*g))*( -r*Ro*sqrt(1/r - 1/Ro) - sqrt(Ro3)(arctan(Ro/r - 1)) //&3
and it doesn't work when using 200, 400, 600 meters
It yields a time which is 55,000,000-fold that of the values calculated using the tower of Pisa-scale formula r = 0.5*g*t2
Is my v(t) formula wrong at &1 ?
Or is my integration wrong in &3?
I've been trying to solve this for two months now, can anybody see an error in my logic?