How Does a Spinning Platform Affect the Period of a Pendulum?

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The discussion focuses on calculating the period of a pendulum mounted on a spinning platform. The pendulum is 2 meters long and experiences a constant angular velocity of 0.12 radians per second. The user is unsure how to determine the radius and incorporate the centripetal force into the period equation. They mention needing to replace the gravitational acceleration with a different force due to the rotation. The conversation highlights the complexity of analyzing pendulum motion in a non-inertial reference frame.
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Homework Statement


A pendulum 2 meters long with a mass of 1kg is mounted on a circular platform on the Earth's surface that's spinning at constant angular velocity of .12 rads/sec. The pendulum is mounted on a pole that's perpendicular to the platform at a distance of 5 meters from the center of rotation.

If it's displaced for its equilibrium position, what will be the period of the pendulum?

P.S. My physics teacher said that the diagrams below explains what's happening:

FROM A BIRD'S EYE VIEW-
http://answerboard.cramster.com/answer-board/image/43e827330329f2500585d3862fc2f7af.jpg

FROM A NORMAL VIEW:
http://answerboard.cramster.com/answer-board/image/2bf7be21984fbe2a0b76f2f86b744710.jpg

Now, he mentioned how we must get the force from the equation F=mv2/r and then get the acceleration from a=F/m, but first I need to get r and I have no clue how to do that since theta isn't given. Then I have to replace the acceleration I get for g in the period equation.
Please help!

Homework Equations


a=F/m
a=v2/r
F=mv2/r

The Attempt at a Solution



No clue!?
 
Last edited by a moderator:
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Do you know how to work out the period of a pendulum that's not on a turntable ?

One of the numbers in the equation is the 'return force' on the bob. You'll need to replace that with a different force for the rotating pendulum.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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