- #1
Alexander2357
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Homework Statement
An infinitely long line of charge has a linear charge density of λ C/m. A proton is at distance d m from the line and is moving directly toward the line with speed v m/s.
How close does the proton get to the line of charge?
Homework Equations
[tex]\Delta KE = W = -\Delta U[/tex]
[tex]\frac{1}{2}m(v_{2})^{2}-\frac{1}{2}m(v_{1})^{2}=\frac{q_{1}q_{2}}{4\pi \epsilon _{0}r_{2}}-\frac{q_{1}q_{2}}{4\pi \epsilon _{0}r_{1}}[/tex]
Potential difference at distance d from an infinite line of charge: [tex]V=\frac{\lambda }{4\pi \epsilon _{0}}\int_{0}^{\infty }\frac{dx}{\sqrt{x^{2}+d^{2}}}[/tex]
Distance from the infinite wire that the electron can reach before being stopped:
[tex]r=d\times e^{\frac{-m(v)^{2}4\pi \epsilon _{0}}{\lambda q}}[/tex]
Where e is Euler's Number.
The Attempt at a Solution
The equation is correct as when I substitutes numbers into it I got the correct answer but how is it derived?