- #1
01SpAcE01
- 24
- 0
So let's say we have a cylindrical pressure vessel of volume 2.4 x 10^-3 m^3 carrying 2 liters of water heated to 130 degrees Celsius, how would I calculate the circumferential pressure inside the container?
radius = 56x10^-3 m
height = 0.24 m
I know the equation would be stress=pressure x radius / thickness. Just never had to calculate the pressure before.
Also, if someone is feeling extra nice, would you mind clrifying this for me please: If steam is created in an environment that has 2 liters of water, but then the element further heats the water to 130 degrees Celsius, then would this create saturated steam or superheated? I always thought superheated, as the vapour must exceed 100 at some point if it is in a sealed environment. I just read something today that confused me somewhat.
radius = 56x10^-3 m
height = 0.24 m
I know the equation would be stress=pressure x radius / thickness. Just never had to calculate the pressure before.
Also, if someone is feeling extra nice, would you mind clrifying this for me please: If steam is created in an environment that has 2 liters of water, but then the element further heats the water to 130 degrees Celsius, then would this create saturated steam or superheated? I always thought superheated, as the vapour must exceed 100 at some point if it is in a sealed environment. I just read something today that confused me somewhat.
Last edited: