- #1
bubokribuck
- 42
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The function f(x) is periodic with period 2[itex]\pi[/itex] and is defined by
f(x) = -cos(x) when -[itex]\pi[/itex]<x<0
= cos(x) when 0<x<[itex]\pi[/itex]
Sketch f from x=-3[itex]\pi[/itex] to 3[itex]\pi[/itex].
My question is, when -[itex]\pi[/itex]<x<0 and 0<x<[itex]\pi[/itex], how am I supposed to graph the function from -3[itex]\pi[/itex] to 3[itex]\pi[/itex]?
f(x) = -cos(x) when -[itex]\pi[/itex]<x<0
= cos(x) when 0<x<[itex]\pi[/itex]
Sketch f from x=-3[itex]\pi[/itex] to 3[itex]\pi[/itex].
My question is, when -[itex]\pi[/itex]<x<0 and 0<x<[itex]\pi[/itex], how am I supposed to graph the function from -3[itex]\pi[/itex] to 3[itex]\pi[/itex]?