- #1
question dude
- 80
- 0
2) My attempt
Take the first interval, 60 - 62, I thought about doing this:
(62 - mean) / standard deviation
(62 - 67.45) / 2.92 = - 1.866
using Z score < - 1.886, from the normal distribution table, I get:
1 - 0.9686 = 0.0314
0.0314*(100) = 3.14
please note 100 is the total observed frequency
As you can see, I get 3.14 instead of 4.13 as given in the expected frequency column.