- #1
tiger1
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[SOLVED] Index of refraction
An air bubble inside an 9.00 cm-diameter plastic ball is 2.90 cm from the surface.
As you look at the ball with the bubble turned toward you, how far beneath the surface does the bubble appear to be?
n_1/s + n_2/s' = n_2-n_1/R
1.59/.0290 + 1/s' = 1-1.5/.045
s'=1.52
I'm not sure why that isn't correct.
...
1.59/.0290+1/s' = 1.59-1/.045
s'=.024m <- correct
Homework Statement
An air bubble inside an 9.00 cm-diameter plastic ball is 2.90 cm from the surface.
As you look at the ball with the bubble turned toward you, how far beneath the surface does the bubble appear to be?
Homework Equations
n_1/s + n_2/s' = n_2-n_1/R
The Attempt at a Solution
1.59/.0290 + 1/s' = 1-1.5/.045
s'=1.52
I'm not sure why that isn't correct.
...
1.59/.0290+1/s' = 1.59-1/.045
s'=.024m <- correct
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