- #1
Victorzaroni
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Homework Statement
A mass M slides down a smooth surface from height h and collides inelastically with the lower end of a rod that is free to rotate about a fixed axis at P as shown below. The mass of the rod is also M, the length is L, and the moment of inertia about P is ML2/3.
The angular velocity of the rod about the axis P just after the mass sticks to it will be:
(A) √(gh/2)
(B) √(2gh)/L
(C) (3/4L)√(2gh)
(D) (3L)/√(2gh)
(E) (9√(2gh))/L
Homework Equations
There's a bunch.
The Attempt at a Solution
I started with conservation of energy, so mgh=(1/2)mv2 and thus v=√(2gh). I don't really know where to go next. I know inelastic means momentum is conserved and kinetic energy is not.