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K.z_z
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If there is a parallel plate capacitor with plate area, A, plate separation, d, and a slab of copper of thickness, b, is inserted exactly halfway between the plates. How to find it's new capacitance, C', and new potential difference, V' ?
Answer: V' = E(d-b) and C' = εA / (d-b)
I understand that there would be no effect on the electric field and E = Vd, and there is no electric field inside the copper. Is this why we exclude the thickness of the copper when calculating V' ? And why also do the same for capacitance? Thank you
Answer: V' = E(d-b) and C' = εA / (d-b)
I understand that there would be no effect on the electric field and E = Vd, and there is no electric field inside the copper. Is this why we exclude the thickness of the copper when calculating V' ? And why also do the same for capacitance? Thank you