Integral of an exponential divided by a root function

In summary, the conversation discusses proving that the diagonals of a parallelogram bisect each other. The equations used are \vec{r_1}=\vec{a}+\vec{b} and \vec{r_2}=\vec{b}-\vec{a}. The question of whether the diagonals go through the center of the parallelogram is raised, along with defining the term "vertex" as the point where two vectors intersect. The conversation concludes with finding the vector that starts at one vertex and ends at the midpoint of \vec{a}+ \vec{b}, which is \vec{b}-\vec{a}.
  • #1
chaoseverlasting
1,050
3

Homework Statement



Prove that the diagonals of a parallelogram bisect each other.

Homework Equations



I chose one vertex as the origin, one as a and one as b. The final vertex was a+b.

The Attempt at a Solution



The diagonals were [tex]\vec{r_1}=\vec{a}+\vec{b}[/tex] and [tex]\vec{r_2}=\vec{b}-\vec{a}[/tex]. Where do I go from here? Can I assume that they go through the center of the parallelogram or do I have to prove that too?
 
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  • #2
What is the definition of a vertex?
 
  • #3
Err... a point where two vectors intersect?
 
  • #4
Your vectors "begin" at one vertex, right? What vector, starting at that vertex, has its "end" at the midpoint of [itex]\vec{a}+ \vec{b}[/itex]? [itex]\vec{b}-\vec{a}[/itex]?
(Note that, since [itex]\vec{b}-\vec{a}[/itex] "starts" at [itex]\vec{a}[/itex] instead of the origin, the midpoint of [itex]\vec{b}-\vec{a}[/itex] is at [itex]\vec{a}[/itex] plus half of [itex]\vec{b}-\vec{a}[/itex].)
 
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Related to Integral of an exponential divided by a root function

1. What is the general form of an integral of an exponential divided by a root function?

The general form of this integral is ∫e^x / √x dx.

2. How do you solve an integral of an exponential divided by a root function?

To solve this type of integral, we can use the substitution method. Let u = √x, then du = 1/2√x dx. This allows us to rewrite the integral as ∫2e^(u^2) du. We can then use integration by parts to solve for the final answer.

3. What is the significance of the exponential and root functions in this integral?

The exponential function e^x represents continuous growth, while the root function √x represents a decreasing rate of change. The combination of these two functions in the integral represents a balance between growth and decay, making it a useful tool in many scientific and mathematical applications.

4. Can this integral be solved without using substitution?

Yes, it is possible to solve this integral without using substitution. One method is to use the power rule for integration, which states that ∫x^n dx = x^(n+1) / (n+1) + C. However, it may be more complex and time-consuming compared to using the substitution method.

5. What are the real-world applications of integrals of exponential divided by a root function?

Integrals of this type can be used to model and analyze various phenomena, such as radioactive decay, population growth, and electrical circuits. They are also commonly used in statistics and probability to calculate the area under a curve and determine probabilities of certain events.

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