- #1
NMadura
Hey All,
I have a plastic vessel fully filled filled with an incompressible fluid (Water), at some time this vessel is impacted and crushed on one side (say 5% of the initial volume is lost).
Only, I know the volume isn't lost, the fluid (being incompressible) will exert pressure on all surfaces of my vessel causing the vessel to expand (where it isn't being crushed) and the pressure of the fluid will increase.
Is there a way of calculating this increase in pressure (maybe as a function of displaced fluid)?
In my mind I picture this as a water balloon on a flat surface, as I push my hand down on the middle of the balloon the water moves to areas not being compressed, eventually the maximum stress of the material is reached and the balloon material fails. How would one predict the internal pressure of the fluid?
Thanks for any help.
I have a plastic vessel fully filled filled with an incompressible fluid (Water), at some time this vessel is impacted and crushed on one side (say 5% of the initial volume is lost).
Only, I know the volume isn't lost, the fluid (being incompressible) will exert pressure on all surfaces of my vessel causing the vessel to expand (where it isn't being crushed) and the pressure of the fluid will increase.
Is there a way of calculating this increase in pressure (maybe as a function of displaced fluid)?
In my mind I picture this as a water balloon on a flat surface, as I push my hand down on the middle of the balloon the water moves to areas not being compressed, eventually the maximum stress of the material is reached and the balloon material fails. How would one predict the internal pressure of the fluid?
Thanks for any help.