- #1
davidbenari
- 466
- 18
I feel like have a chicken and egg type of problem regarding internal resistences because of the following problem:
The voltage across a battery with internal resistence is given by the equation
EMF-Ir=V
Given the voltage across the battery then the voltage in the circuit is
V=IR
So, if I have more current then my voltage decreases, if I have less voltage then my current decrease because of V=IR.
So what's happening here?
If I have an increase in current, then it immediately drops?
Thanks.
The voltage across a battery with internal resistence is given by the equation
EMF-Ir=V
Given the voltage across the battery then the voltage in the circuit is
V=IR
So, if I have more current then my voltage decreases, if I have less voltage then my current decrease because of V=IR.
So what's happening here?
If I have an increase in current, then it immediately drops?
Thanks.