Intro to Nuclear Engineering Help

[luca131]

Homework Statement

If 57.5% of the fission neutrons escape from a bare sphere of 235 Uranium, what is the multiplication factor of the sphere?. In this system, the average value of nu being 2.31.

Homework Equations

nu= number of neutrons emitted per absorption in the fuel

The Attempt at a Solution

Very basic problem, yet wanted to check my answer and understanding of it.
Since 57.5% of the fission neutrons escape, that means 42.5% of the fission neutrons are being used. So for every 1 fission neutron used 2.31 fission neutrons are being emitted. So the multiplication factor for the system would be .425(2.31)= 0.982, thus stating the reactor is subcritical, since the multiplication factor is less than 1.

 

[KataKoniK]

Thank you for your question. Your understanding and solution to this problem are correct. The multiplication factor of the bare sphere of 235 Uranium is indeed 0.982, indicating that the reactor is subcritical and cannot sustain a chain reaction. This is an important factor to consider in nuclear reactor design and safety.

One thing to note is that the multiplication factor is also dependent on other factors such as the density and geometry of the fuel, as well as the presence of any moderators or reflectors. Therefore, in a real-world scenario, the multiplication factor may vary and must be carefully controlled to ensure safe and efficient operation of a nuclear reactor.

I hope this helps clarify your understanding of this problem. Keep up the good work in your studies as a scientist!

Scientist

 

[Mene]

I would like to commend you on your understanding of the problem and your attempt at solving it. Your approach is correct and your solution is accurate. The multiplication factor is indeed less than 1, indicating a subcritical reactor. Keep up the good work!