You don't need the height but you got it OK. What is your problem? I cannot read the image you posted. It is not clear enough.danielsmith123123 said:
The maximum height of a ball thrown vertically can be calculated using the formula: h = (v2sin2θ)/2g, where h is the maximum height, v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity.
Time plays a crucial role in determining the maximum height of a ball thrown vertically. The time taken by the ball to reach its maximum height is half of the total time of flight. This is because the ball reaches its highest point when its vertical velocity becomes zero, and then starts to fall back down due to the force of gravity.
The initial velocity has a direct impact on the maximum height of a ball thrown vertically. The higher the initial velocity, the higher the maximum height reached by the ball. This is because a higher initial velocity means the ball has more energy, which allows it to overcome the force of gravity and reach a greater height.
Yes, the angle of projection can affect the maximum height of a ball thrown vertically. The maximum height is achieved when the angle of projection is 90 degrees, i.e. when the ball is thrown straight up. As the angle decreases, the maximum height also decreases because the vertical component of the initial velocity decreases, resulting in a lower maximum height.
Several factors can cause the actual maximum height of a ball to differ from the calculated maximum height. These include air resistance, the shape and size of the ball, and external forces such as wind. In real-life scenarios, it is difficult to account for all these factors, which can result in a slight difference between the calculated and actual maximum height of a ball thrown vertically.