- #1
- 7,011
- 10,493
Hi, All:
The Wikipedia page on symplectic matrices:
http://en.wikipedia.org/wiki/Symplectic_vector_space ,
claims that symplectic matrices are invertible
, i.e., skew-symmetric nxn-
matrix with entries w(b_i,b_j) , satisfying the properties:
i)w(b_i,b_i)=0
ii)w(b_i,b_j)=-w(b_j,b_i)
iii)w(b_i,.)=0 , i.e., w(b_i,b_j)=0 for all b_j
are invertible.
Even for small n , calculating the determinant seems to get out of hand;
Is there an easy way of seeing this?
TIA
Thanks.
iii)w(bi,.)=0 , then bi=0
The Wikipedia page on symplectic matrices:
http://en.wikipedia.org/wiki/Symplectic_vector_space ,
claims that symplectic matrices are invertible
, i.e., skew-symmetric nxn-
matrix with entries w(b_i,b_j) , satisfying the properties:
i)w(b_i,b_i)=0
ii)w(b_i,b_j)=-w(b_j,b_i)
iii)w(b_i,.)=0 , i.e., w(b_i,b_j)=0 for all b_j
are invertible.
Even for small n , calculating the determinant seems to get out of hand;
Is there an easy way of seeing this?
TIA
Thanks.
iii)w(bi,.)=0 , then bi=0