Is the Gambler's Fallacy Really a Fallacy?

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The discussion centers on the Gambler's Fallacy and the nature of randomness in independent events, particularly in gambling scenarios like roulette. Participants argue about the probability of consecutive outcomes, asserting that while shorter strings of identical results are more common, each individual outcome remains independent with a consistent probability. There is a debate over whether the occurrence of many identical outcomes affects the likelihood of subsequent outcomes, with some insisting that the chance of a specific outcome does not change based on prior results. The conversation highlights misunderstandings of probability principles, particularly the Law of Large Numbers, and emphasizes the need for practical experimentation to clarify these concepts. Ultimately, the consensus is that while patterns may appear, they do not influence future independent events in a random system.
  • #51
Question:

Would you believe that the following sequence of numbers is random:

010101010101010101010101010101010101010101010101010101010101010101010101010101

Why (not)?
 
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  • #52
Volkl said:
Imagine a longer set? You would be even more incorrect as the length approaches infinity.

The probability of drawing a red marble, then a black marble, then a red marble out of a bag is 1/8. The probability of drawing 2 consecutive black marbles out of a bag is 1/4. I was taught this when I took pre-algebra in 6th grade.
 
  • #53
Do you think there are just as many sets of 100 blacks in a row as there are individual blacks? Do you really need a simulation for this?
 
  • #54
Volkl said:
Do you think there are just as many sets of 100 blacks in a row as there are individual blacks?

Nobody is claiming this.
 
  • #55
The same concept holds true when comparing to 99, or 98, or 97...or 2. Doesn't it?
 
  • #56
Please answer this:

micromass said:
Question:

Would you believe that the following sequence of numbers is random:

010101010101010101010101010101010101010101010101010101010101010101010101010101

Why (not)?
 
  • #57
Sure it is likely to be random because the values change, values tend to like doing that when things are random.
 
  • #58
No one has mentioned the Binomial Theorem and the Bernoulli Trial Formula.
For any finite sequence with known probability, these laws govern the outcomes.
I don't have time today to give a detailed example, but maybe someone can pick up the ball here for me.

Probability is fascinating partly because one single word or one misinterpretation can completely change a problem solution from correct to incorrect.

And like all Fallacies, The Gambler's Fallacy "seems to be true" only because the language obscures the whole truth of the situation.
 
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  • #59
So you believe that a sequence of 500000000 alternating occurences of 01010101 could occur in nature?? Wow...
 
  • #60
  • #61
Volkl said:
Sure it is likely to be random because the values change, values tend to like doing that when things are random.
You can not seriously believe that !
Endless 0101010101 ... looks random to you ?

If someone took a deck of playing cards and turned them over one at a time and they came out Red Black Red Black all the way thru the deck, you would NOT think the deck was stacked ? You would believe that was a true random outcome ?
If so, how could you ever tell if a pair of dice or a roulette table was weighted ?
 
  • #62
The chances of the values all being alternating is the same as them all being alike. I already talked about this being basically impossible previously.

Let me ask you this, if you believe that 100 blacks in a row will be less prevalent than ten blacks in a row, then how does this come about? What is the rule and is it not implemented by alternating the colour sooner rather then later?
 
  • #63
This is in the context of the original question which is a sample size of 50,000,000.
 
  • #64
Because:

1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2

>

1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2
 
  • #65
Volkl said:
Let me ask you this, if you believe that 100 blacks in a row will be less prevalent than ten blacks in a row, then how does this come about? What is the rule and is it not implemented by alternating the colour sooner rather then later?
You're still arguing that 'regression to the mean' is enforced by some higher power.

i.e. Given that highly unlikely events are usually followed by less unlikely events, you are saying it is because 'nature demands it' while in truth it's just that the probability that two unlikely events will happen is lower than one unlikely and one likely.

You don't lose the lottery the week after a big win because 'nature demands it to make up the numbers', it's just that the probability for each win is low, and the probability for both wins in a row is even lower. You can do the numbers to prove it.

Independent results (such as red/black on a roulette wheel) are independent. EVERY spin has a 50/50 chance of each.
 
  • #66
We should be comparing the total number of groups of ten to the total number of groups of 100. Do you believe the total number of groups of 10 as related to 100 would be in the same ratio as the ratio of probabilities you displayed?
 
  • #67
Well in theory
I think it is a safe bet to say that the chances of 100 blacks in a row is less likely than 10 in a row in the same way as I believe 11 blacks in a row is less likely than ten.
 
  • #68
If you wait for ten blacks in a row and bet against black only in this situation I.e(after ten blacks in a row), you will win more than 50 percent of the time, because it is less likely to have 11 blacks in a row over time.
 
  • #69
Volkl said:
If you wait for ten blacks in a row and bet against black only in this situation I.e(after ten blacks in a row), you will win more than 50 percent of the time, because it is less likely to have 11 blacks in a row over time.
No. This statement is exactly the gambler's fallacy.

You will win exactly 50% of the time.

The chances of BBBBBBBBBBB is the same as BBBBBBBBBBR. Pick any specific 11-long sequence and it will have the same probability of any other 11-long sequence.

Turning your thought-experiment around, you could also say you should bet on black, because BBBBBBBBBBR is a very unlikely result. Or "if you wait for BRBRBRBRBR then you should bet on R because continuing that sequence is unlikely", which is just as false.
 
  • #70
Volkl said:
If I was a serious gambler there is a small chance that I could place 50,000,000 bets physically at a casino. Pretending that the game we are playing offers fair odds, the chances of one particular outcome coming up 1000 times in a row within the set compared to the same particular outcome coming up 100 times must be much less. If this is true the probability of 20 particular outcomes in a row must be less then the probability that 10 of the same particular outcomes can come up. Doesn't this prove that there is a tendency towards randomness meaning that there is a tendency to have less of the same particular value coming up in a row. To me, this logic proves that the gamblers fallacy is in itself a fallacy. Or do you believe that all 50,000,000 could be the same value for anyone living on earth? I had a roulette wheel with no greens in mind.
This is the single most ridiculous thread I have ever seen on this forum...

There are many ways to think about the Gambler's fallacy. Here's a simple logical argument that shows that the Gambler's fallacy cannot be true:

Suppose you have a coin that has a 50% probability of flipping heads and that coin flipped heads n times in a row. What are the chances of flipping heads a subsequent time? If that probability is anything other than 50% then you are contradicting the initial supposition that you had a coin that "has a 50% probability of flipping heads," therefore the only logically consistent conclusion is that that is the true probability. QED
 
  • #71
Volkl said:
The logic here does not require a computer. The point is that there is a higher probability that smaller sets of like numbers occur than larger sets of like numbers, so there is a tendency for the next value to oppose the previous string of like values.
While one could determine the nature of this phenomena without a computer, it appears that you're the sort of person who needs one. Even if you think you don't, perhaps you can simply humour the posters in this thread by making the computer simulation... unless you secretly know that reality will not favour your theory...
 
  • #72
Volkl said:
How can the probability for 1000 blacks in a row be less than a hundred in a row if there was no tendency towards randomness?
You ask this question in many different ways in this thread:
Volkl said:
Why are smaller sets of blacks more prevalent than larger sets of blacks then?
Volkl said:
If the Strings of blacks have different probabilities, but yet the individual spin outcomes have the same probability, what accounts for the strings of blacks having different probabilities?
The answer is simple: smaller strings are more probable than larger strings because there are less conditions to satisfy...

For example, let's suppose that roulette tosses are random and independent events. The reason why the chances of tossing 2 blacks are better than tossing 10 blacks is because, for the previous case, there are only two conditions to satisfy: that the first toss is black and that the second one is too. For the latter case, you have to satisfy all 10 independent conditions with the same odds for each toss. That will be much harder to do and consequently happens much less often...
 
  • #73
Volkl said:
micromass said:
Not only that: shorter strings of a certain outcome (not necessarily like) are more prevalent than larger strings of a certain outcome.

That is: you will see more of the string

BRBRBRBBB

then of the string

BRBRBRBBBRRBRBBRBBRRRBBRB

So whether the outcomes are all black is irrelevant.
If that is true then counting all the way up to a thousand following your same logic would mean that the 1000 has the same probability as the 100. Something is not right here and it has to do with the tendency for the string itself to be random as opposed to like valued I.e. All blacks.
Why do you say this? This makes no sense. How does micromass' statement imply what you're saying? If you were to try to construct a formally logical argument, you will find yourself unable to build the implication...
 
  • #74
Volkl said:
If you wait for ten blacks in a row and bet against black only in this situation I.e(after ten blacks in a row), you will win more than 50 percent of the time, because it is less likely to have 11 blacks in a row over time.
If you believe this then please describe for us how much more than 50% will you win? Care to calculate what you think the odds should be?
 
  • #75
Volkl said:
If you wait for ten blacks in a row and bet against black only in this situation I.e(after ten blacks in a row), you will win more than 50 percent of the time, because it is less likely to have 11 blacks in a row over time.

After sleeping on this for 2 nights, I think I am able to see where your brain is coming from. I still do not agree, but perhaps if I address this from another angle.

IF all the flips/tosses/spins etc. have already been made and you have a block of data, any number of sets, and you start randomly selecting data from the previously made set, and you select different lengths of strings, say 5 and 6, you will find, statistically, more strings of 5 than you will of 6 for any pattern you choose. HOWEVER, this is only because the likelihood of any specific 5-string is higher than any specific 6-string.

If you, on the other hand, start flipping/tossing/spinning etc., from scratch, and are not shown the results, would you not suspect that you have a 1/n chance of guessing right each time? Each selection is COMPLETELY unrelated to the previous ones.

However, I still think that you should create a computer simulation to verify your predictions. It could be a relatively short code (definitely no more than 50-100 lines).
 
  • #76
Volkl said:
If you wait for ten blacks in a row and bet against black only in this situation I.e(after ten blacks in a row), you will win more than 50 percent of the time, because it is less likely to have 11 blacks in a row over time.

As has already been suggested, I highly suggest you simply write a simulation program and test these ideas first hand.

In fact, you don't even really need a real program. Go here:
http://www.random.org/files/
Save one of the text files (warning they are about 2 megs each), open it up and search for the string '111111111', every time you find it check what the next number is. You will find it is equally likely to be 1 or 0.

Consider what would have to be true otherwise. The source of randomness (roulette wheel or radioactive decay) would somehow have to 'know' what the previous results were and be influenced by them. What if you looked at an entire casino's worth of roulette wheels at once, combining all the results into one giant stream of reds and blacks. However, someone else looked at just a single wheel. If the single wheel had a streak of blacks, but the casino as a whole was on a red streak, what would that individual wheel be more likely to produce? Now, what if you look at all the casinos on Earth? What if you come up with some complex method to combine the results (eg 10 from one wheel, 3 from the next, 17 from the next, alternating between wheels #4 and #5 for 20 choices after that, etc)? It should be clear there would be an infinite number of ways you could combine the data from many wheels. How could there still be a force influencing the results when the data could be combined to produce streaks in any different way?

To use an example I've seen before somewhere, imagine you had a standard fair coin, and flipped it until a long streak occurred (say 10 heads). Now you put the coin in a jar with many other coins and shook it up. Would that single coin still want to be tails? What if you chose another random coin, would it tend to be tails? What if you spent the coin, and a new person who knew nothing of this flipped it, would it still tend to be tails? What if you redefined tails as the side with a picture of a face, and heads as the side with a picture of a bird (or whatever it is)? Now would it tend to be tails (as you defined it), or the 'real' tails?

My point in all this is that when you start to think that sources of randomness are influenced by past events, it leads to many silly outcomes. There are simply too many systems you could use to combine events to produce random choices, and those systems would contradict each other if there were a force which tended to reverse long streaks.

Again, you really should just write a program to test this. You could also just use a spreadsheet. Or, you could actually get a coin and start flipping it. Every time a streak of 3 comes up make a bet against the streak continuing to 4. Keep track of you total winnings.
 
  • #77
It's nice to see that people are finally coming around. Does everyone agree that the computer simulation that you are all desperate for would reveal that 100 blacks in a row would be less prevalent than 10 blacks in a row? Then why wouldn't that same logic hold true for 11 blacks in a row being less prevalent than 10 blacks in a row? Staying within the 50,000,000 trials.

If these are true most humans would experience a higher probability that red would come up after 10 blacks in a row.

-----------------------------------------

Not that anyone mentioned it yet but the error with this logic might be that the 10 blacks in a row case should not be directly comparable to the 11 blacks in a row case, because, the ten blacks in a row case also comes within all large cases of blacks in row. This was not easy for me to see sorry for putting so much gusto into some of the earlier responses, or for frustrating the hell out of people, either way, I played baccarat this weekend and won, some how it varies at an even higher rate then roulette - but that's another theory for a different thread.
 
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  • #78
Volkl said:
It's nice to see that people are finally coming around. Does everyone agree that the computer simulation that you are all desperate for would reveal that 100 blacks in a row would be less prevalent than 10 blacks in a row? Then why wouldn't that same logic hold true for 11 blacks in a row being less prevalent than 10 blacks in a row. Staying within the 50,000,000 trials.

If these are true most humans would experience a higher probability that red would come up after 10 blacks in a row.

-----------------------------------------

Not that anyone mentioned it yet but the error with this logic might be that the 10 blacks in a row case should not be directly comparable to the 11 blacks in a row case, because, the ten blacks in a row case also comes within all large cases of blacks in row. This was not easy for me to see sorry for putting so much gusto into some of the earlier responses, or for frustrating the hell out of people, either way, I played baccarat this weekend and won, some how it varies at an even higher rate then roulette - but that's another theory for a different thread.

Nobody is claiming here that 11 blacks are as prevalent as 10 blacks. Everybody knows I would see 10 blacks more often than 11 blacks. That's not the point.
 
  • #79
Please don't feed the troll. Please report threads like this.
 

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