- #1
Rahulx084
- 99
- 1
Wikipedia says,
Unlike a free expansion , in Joule Thomson expansion work is done causing the change in internal energy. Whether the internal energy increases or decreases is determined by whether work is done on or by the fluid; that is determined by the initial and final states of the expansion and properties of the fluid.
How we would determine work done by or on the gas in this expansion?
This is what I was thinking,
Work done before the porous plug = -(Pressure of gas before throttling)/(density of the gas before throttling)= W1
Work done after throttling= +(Pressure of gas after expansion)/(Density of the gas after throttling)= W2
Total Work(W)= W1+W2
If W >0 , then the gas cools down
W<0 , then the gas heats up
Am I going in right direction?
I have considered work done by system as positive in sign convention.
[Moderator's note: Moved from a technical forum and thus no template.]
Unlike a free expansion , in Joule Thomson expansion work is done causing the change in internal energy. Whether the internal energy increases or decreases is determined by whether work is done on or by the fluid; that is determined by the initial and final states of the expansion and properties of the fluid.
How we would determine work done by or on the gas in this expansion?
This is what I was thinking,
Work done before the porous plug = -(Pressure of gas before throttling)/(density of the gas before throttling)= W1
Work done after throttling= +(Pressure of gas after expansion)/(Density of the gas after throttling)= W2
Total Work(W)= W1+W2
If W >0 , then the gas cools down
W<0 , then the gas heats up
Am I going in right direction?
I have considered work done by system as positive in sign convention.
[Moderator's note: Moved from a technical forum and thus no template.]
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