- #1
Carlos de Meo
- 23
- 2
Hi Guys
I´m studying the absorption and emission phenomena of a gas and, according to Kirchhoff "extended" law, for a body at thermodynamic equilibrium, the following statement is true.
ελ(T,θ,φ) = Aλ(T, θ,φ).
So, if i understood correctly the meaning of this equation, The amount of absorbed energy must be emitted with the same probability at all direction at the same wavelength, is it correct?
If so, the only difference between reflection and emission at equilibrium (in therms of energy) is that i´m able to predict the direction of the reflected photon (assuming specular reflection) and for the absorption/emission phenomena, i can only say that it happens with the same probability through all direction?
Thank you very much for your time and patience
I´m studying the absorption and emission phenomena of a gas and, according to Kirchhoff "extended" law, for a body at thermodynamic equilibrium, the following statement is true.
ελ(T,θ,φ) = Aλ(T, θ,φ).
So, if i understood correctly the meaning of this equation, The amount of absorbed energy must be emitted with the same probability at all direction at the same wavelength, is it correct?
If so, the only difference between reflection and emission at equilibrium (in therms of energy) is that i´m able to predict the direction of the reflected photon (assuming specular reflection) and for the absorption/emission phenomena, i can only say that it happens with the same probability through all direction?
Thank you very much for your time and patience