- #1
Praveen1901
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- Homework Statement
- When steady state is reached by keeping switch in position 1, then switch 'S' is transferred to position 2, then:
(A) Charge on 3F capacitor is 30C after S is transferred from position 1 to 2.
(B)Charge on 3F capacitor is 650/19 C after S is transferred from 1 to 2.
(C) Work done by battery 380 J after switch S is transferred from 1 to 2.
(D) Work done by battery is 80 J after S is transferred from 1 to 2.
- Relevant Equations
- Q=CV
Equivalent capacitance before and after remains the same.
Now the 10F capacitor (which was initially connected in parallel with 20F) would have 30 C charge. Hence an additional 20C must have been supplied to it. The only path which may supply the charge is through battery. However this leads to 6F capacitor having an additional charge of 20C as well. But in steady state the charge on it should have been the same as equivalent capacitance remained the same before and after
I'm unable to apply kirchhoffs law correctly here.
Now the 10F capacitor (which was initially connected in parallel with 20F) would have 30 C charge. Hence an additional 20C must have been supplied to it. The only path which may supply the charge is through battery. However this leads to 6F capacitor having an additional charge of 20C as well. But in steady state the charge on it should have been the same as equivalent capacitance remained the same before and after
I'm unable to apply kirchhoffs law correctly here.