- #1
ISuckAtMath
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we are given B = CAC^-1
Prove that A and B have the same characteristic polynomial
given a hint: explain why ƛIn = CƛInC^-1
what I did was:
B = CAC^-1
BC = CA
Det(BC) = Det(CA)
Det(B) Det(C) = Det(C) Det(A)
Now they’re just numbers so I divide both sides by Det(C)
Det(B) = Det(A)
not I am stuck
Prove that A and B have the same characteristic polynomial
given a hint: explain why ƛIn = CƛInC^-1
what I did was:
B = CAC^-1
BC = CA
Det(BC) = Det(CA)
Det(B) Det(C) = Det(C) Det(A)
Now they’re just numbers so I divide both sides by Det(C)
Det(B) = Det(A)
not I am stuck