- #1
scienceman111
- 2
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I am trying to calculate the strength of the magnetic field ( in teslas ) that would be needed to deflect cosmic rays going about 99% the speed of light.
using the lorents force
http://en.wikipedia.org/wiki/Lorentz_force
I replaced force with mass times acceleration
I canceled the cross product because for this case pretend that the cosmic ray hits the magnetic field perpendicularly(eliminating the cross product)
the variable E is also canceled because I am not applying an electric force
so I end up with B= (mass times accleration) divided by (the charge in coloumbs times the velocity (99% the speed of light))
but correct me if I am wrong. I have the accleration of cosmic rays to be 10,000 m/s squared until it reaches its maximum speed
but because I am dividing by the spped of light(almost)
I end up with a (insert a huge decimal number here) Teslas
which must be incorrect because it would take many teslas to deflect cosmioc rays
PLEASE CORRECT ME
Thanks.
using the lorents force
http://en.wikipedia.org/wiki/Lorentz_force
I replaced force with mass times acceleration
I canceled the cross product because for this case pretend that the cosmic ray hits the magnetic field perpendicularly(eliminating the cross product)
the variable E is also canceled because I am not applying an electric force
so I end up with B= (mass times accleration) divided by (the charge in coloumbs times the velocity (99% the speed of light))
but correct me if I am wrong. I have the accleration of cosmic rays to be 10,000 m/s squared until it reaches its maximum speed
but because I am dividing by the spped of light(almost)
I end up with a (insert a huge decimal number here) Teslas
which must be incorrect because it would take many teslas to deflect cosmioc rays
PLEASE CORRECT ME
Thanks.